3.3.58 \(\int \frac {1}{1+\tanh ^3(x)} \, dx\) [258]

Optimal. Leaf size=38 \[ \frac {x}{2}-\frac {2 \text {ArcTan}\left (\frac {1-2 \tanh (x)}{\sqrt {3}}\right )}{3 \sqrt {3}}-\frac {1}{6 (1+\tanh (x))} \]

[Out]

1/2*x-2/9*arctan(1/3*(1-2*tanh(x))*3^(1/2))*3^(1/2)-1/6/(1+tanh(x))

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Rubi [A]
time = 0.05, antiderivative size = 38, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 8, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.625, Rules used = {3742, 2099, 213, 632, 210} \begin {gather*} -\frac {2 \text {ArcTan}\left (\frac {1-2 \tanh (x)}{\sqrt {3}}\right )}{3 \sqrt {3}}+\frac {x}{2}-\frac {1}{6 (\tanh (x)+1)} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(1 + Tanh[x]^3)^(-1),x]

[Out]

x/2 - (2*ArcTan[(1 - 2*Tanh[x])/Sqrt[3]])/(3*Sqrt[3]) - 1/(6*(1 + Tanh[x]))

Rule 210

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[-b, 2])^(-1))*ArcTan[Rt[-b, 2]*(x/Rt[-a, 2])
], x] /; FreeQ[{a, b}, x] && PosQ[a/b] && (LtQ[a, 0] || LtQ[b, 0])

Rule 213

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(-(Rt[-a, 2]*Rt[b, 2])^(-1))*ArcTanh[Rt[b, 2]*(x/Rt[-a, 2])]
, x] /; FreeQ[{a, b}, x] && NegQ[a/b] && (LtQ[a, 0] || GtQ[b, 0])

Rule 632

Int[((a_.) + (b_.)*(x_) + (c_.)*(x_)^2)^(-1), x_Symbol] :> Dist[-2, Subst[Int[1/Simp[b^2 - 4*a*c - x^2, x], x]
, x, b + 2*c*x], x] /; FreeQ[{a, b, c}, x] && NeQ[b^2 - 4*a*c, 0]

Rule 2099

Int[(P_)^(p_)*(Q_)^(q_.), x_Symbol] :> With[{PP = Factor[P]}, Int[ExpandIntegrand[PP^p*Q^q, x], x] /;  !SumQ[N
onfreeFactors[PP, x]]] /; FreeQ[q, x] && PolyQ[P, x] && PolyQ[Q, x] && IntegerQ[p] && NeQ[P, x]

Rule 3742

Int[((a_) + (b_.)*((c_.)*tan[(e_.) + (f_.)*(x_)])^(n_))^(p_), x_Symbol] :> With[{ff = FreeFactors[Tan[e + f*x]
, x]}, Dist[c*(ff/f), Subst[Int[(a + b*(ff*x)^n)^p/(c^2 + ff^2*x^2), x], x, c*(Tan[e + f*x]/ff)], x]] /; FreeQ
[{a, b, c, e, f, n, p}, x] && (IntegersQ[n, p] || IGtQ[p, 0] || EqQ[n^2, 4] || EqQ[n^2, 16])

Rubi steps

\begin {align*} \int \frac {1}{1+\tanh ^3(x)} \, dx &=\text {Subst}\left (\int \frac {1}{\left (1-x^2\right ) \left (1+x^3\right )} \, dx,x,\tanh (x)\right )\\ &=\text {Subst}\left (\int \left (\frac {1}{6 (1+x)^2}-\frac {1}{2 \left (-1+x^2\right )}+\frac {1}{3 \left (1-x+x^2\right )}\right ) \, dx,x,\tanh (x)\right )\\ &=-\frac {1}{6 (1+\tanh (x))}+\frac {1}{3} \text {Subst}\left (\int \frac {1}{1-x+x^2} \, dx,x,\tanh (x)\right )-\frac {1}{2} \text {Subst}\left (\int \frac {1}{-1+x^2} \, dx,x,\tanh (x)\right )\\ &=\frac {x}{2}-\frac {1}{6 (1+\tanh (x))}-\frac {2}{3} \text {Subst}\left (\int \frac {1}{-3-x^2} \, dx,x,-1+2 \tanh (x)\right )\\ &=\frac {x}{2}-\frac {2 \tan ^{-1}\left (\frac {1-2 \tanh (x)}{\sqrt {3}}\right )}{3 \sqrt {3}}-\frac {1}{6 (1+\tanh (x))}\\ \end {align*}

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Mathematica [A]
time = 0.07, size = 49, normalized size = 1.29 \begin {gather*} \frac {1}{36} \left (8 \sqrt {3} \text {ArcTan}\left (\frac {-1+2 \tanh (x)}{\sqrt {3}}\right )-9 \log (1-\tanh (x))+9 \log (1+\tanh (x))-\frac {6}{1+\tanh (x)}\right ) \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(1 + Tanh[x]^3)^(-1),x]

[Out]

(8*Sqrt[3]*ArcTan[(-1 + 2*Tanh[x])/Sqrt[3]] - 9*Log[1 - Tanh[x]] + 9*Log[1 + Tanh[x]] - 6/(1 + Tanh[x]))/36

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Maple [A]
time = 0.34, size = 41, normalized size = 1.08

method	result	size
derivativedivides	\(-\frac {\ln \left (\tanh \left (x \right )-1\right )}{4}-\frac {1}{6 \left (1+\tanh \left (x \right )\right )}+\frac {\ln \left (1+\tanh \left (x \right )\right )}{4}+\frac {2 \sqrt {3}\, \arctan \left (\frac {\left (2 \tanh \left (x \right )-1\right ) \sqrt {3}}{3}\right )}{9}\)	\(41\)
default	\(-\frac {\ln \left (\tanh \left (x \right )-1\right )}{4}-\frac {1}{6 \left (1+\tanh \left (x \right )\right )}+\frac {\ln \left (1+\tanh \left (x \right )\right )}{4}+\frac {2 \sqrt {3}\, \arctan \left (\frac {\left (2 \tanh \left (x \right )-1\right ) \sqrt {3}}{3}\right )}{9}\)	\(41\)
risch	\(\frac {x}{2}-\frac {{\mathrm e}^{-2 x}}{12}+\frac {i \sqrt {3}\, \ln \left ({\mathrm e}^{2 x}+i \sqrt {3}\right )}{9}-\frac {i \sqrt {3}\, \ln \left ({\mathrm e}^{2 x}-i \sqrt {3}\right )}{9}\)	\(47\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(1+tanh(x)^3),x,method=_RETURNVERBOSE)

[Out]

-1/4*ln(tanh(x)-1)-1/6/(1+tanh(x))+1/4*ln(1+tanh(x))+2/9*3^(1/2)*arctan(1/3*(2*tanh(x)-1)*3^(1/2))

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Maxima [B] Leaf count of result is larger than twice the leaf count of optimal. 73 vs. \(2 (29) = 58\).
time = 0.47, size = 73, normalized size = 1.92 \begin {gather*} \frac {2}{9} \, \sqrt {3} \arctan \left (\frac {1}{6} \cdot 3^{\frac {3}{4}} \sqrt {2} {\left (2 \, \sqrt {3} e^{\left (-x\right )} + 3^{\frac {1}{4}} \sqrt {2}\right )}\right ) - \frac {2}{9} \, \sqrt {3} \arctan \left (\frac {1}{6} \cdot 3^{\frac {3}{4}} \sqrt {2} {\left (2 \, \sqrt {3} e^{\left (-x\right )} - 3^{\frac {1}{4}} \sqrt {2}\right )}\right ) + \frac {1}{2} \, x - \frac {1}{12} \, e^{\left (-2 \, x\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+tanh(x)^3),x, algorithm="maxima")

[Out]

2/9*sqrt(3)*arctan(1/6*3^(3/4)*sqrt(2)*(2*sqrt(3)*e^(-x) + 3^(1/4)*sqrt(2))) - 2/9*sqrt(3)*arctan(1/6*3^(3/4)*
sqrt(2)*(2*sqrt(3)*e^(-x) - 3^(1/4)*sqrt(2))) + 1/2*x - 1/12*e^(-2*x)

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Fricas [B] Leaf count of result is larger than twice the leaf count of optimal. 95 vs. \(2 (29) = 58\).
time = 0.36, size = 95, normalized size = 2.50 \begin {gather*} \frac {18 \, x \cosh \left (x\right )^{2} + 36 \, x \cosh \left (x\right ) \sinh \left (x\right ) + 18 \, x \sinh \left (x\right )^{2} - 8 \, {\left (\sqrt {3} \cosh \left (x\right )^{2} + 2 \, \sqrt {3} \cosh \left (x\right ) \sinh \left (x\right ) + \sqrt {3} \sinh \left (x\right )^{2}\right )} \arctan \left (-\frac {\sqrt {3} \cosh \left (x\right ) + \sqrt {3} \sinh \left (x\right )}{3 \, {\left (\cosh \left (x\right ) - \sinh \left (x\right )\right )}}\right ) - 3}{36 \, {\left (\cosh \left (x\right )^{2} + 2 \, \cosh \left (x\right ) \sinh \left (x\right ) + \sinh \left (x\right )^{2}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+tanh(x)^3),x, algorithm="fricas")

[Out]

1/36*(18*x*cosh(x)^2 + 36*x*cosh(x)*sinh(x) + 18*x*sinh(x)^2 - 8*(sqrt(3)*cosh(x)^2 + 2*sqrt(3)*cosh(x)*sinh(x
) + sqrt(3)*sinh(x)^2)*arctan(-1/3*(sqrt(3)*cosh(x) + sqrt(3)*sinh(x))/(cosh(x) - sinh(x))) - 3)/(cosh(x)^2 +
2*cosh(x)*sinh(x) + sinh(x)^2)

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Sympy [B] Leaf count of result is larger than twice the leaf count of optimal. 102 vs. \(2 (36) = 72\).
time = 0.25, size = 102, normalized size = 2.68 \begin {gather*} \frac {9 x \tanh {\left (x \right )}}{18 \tanh {\left (x \right )} + 18} + \frac {9 x}{18 \tanh {\left (x \right )} + 18} + \frac {4 \sqrt {3} \tanh {\left (x \right )} \operatorname {atan}{\left (\frac {2 \sqrt {3} \tanh {\left (x \right )}}{3} - \frac {\sqrt {3}}{3} \right )}}{18 \tanh {\left (x \right )} + 18} + \frac {4 \sqrt {3} \operatorname {atan}{\left (\frac {2 \sqrt {3} \tanh {\left (x \right )}}{3} - \frac {\sqrt {3}}{3} \right )}}{18 \tanh {\left (x \right )} + 18} - \frac {3}{18 \tanh {\left (x \right )} + 18} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+tanh(x)**3),x)

[Out]

9*x*tanh(x)/(18*tanh(x) + 18) + 9*x/(18*tanh(x) + 18) + 4*sqrt(3)*tanh(x)*atan(2*sqrt(3)*tanh(x)/3 - sqrt(3)/3
)/(18*tanh(x) + 18) + 4*sqrt(3)*atan(2*sqrt(3)*tanh(x)/3 - sqrt(3)/3)/(18*tanh(x) + 18) - 3/(18*tanh(x) + 18)

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Giac [A]
time = 0.41, size = 25, normalized size = 0.66 \begin {gather*} \frac {2}{9} \, \sqrt {3} \arctan \left (\frac {1}{3} \, \sqrt {3} e^{\left (2 \, x\right )}\right ) + \frac {1}{2} \, x - \frac {1}{12} \, e^{\left (-2 \, x\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1+tanh(x)^3),x, algorithm="giac")

[Out]

2/9*sqrt(3)*arctan(1/3*sqrt(3)*e^(2*x)) + 1/2*x - 1/12*e^(-2*x)

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Mupad [B]
time = 0.10, size = 38, normalized size = 1.00 \begin {gather*} \frac {\frac {x}{2}+\frac {\mathrm {tanh}\left (x\right )}{6}+\frac {x\,\mathrm {tanh}\left (x\right )}{2}}{\mathrm {tanh}\left (x\right )+1}+\frac {2\,\sqrt {3}\,\mathrm {atan}\left (\frac {\sqrt {3}\,\left (2\,\mathrm {tanh}\left (x\right )-1\right )}{3}\right )}{9} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(tanh(x)^3 + 1),x)

[Out]

(x/2 + tanh(x)/6 + (x*tanh(x))/2)/(tanh(x) + 1) + (2*3^(1/2)*atan((3^(1/2)*(2*tanh(x) - 1))/3))/9

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